sort
- sort BLOCK LIST
- sort LIST
In list context, this sorts the LIST and returns the sorted list value. In scalar context, the behaviour of sort is undefined.
If SUBNAME or BLOCK is omitted, sorts in standard string comparison order. If SUBNAME is specified, it gives the name of a subroutine that returns an integer less than, equal to, or greater than
, depending on how the elements of the list are to be ordered. (The
<=>
andcmp
operators are extremely useful in such routines.) SUBNAME may be a scalar variable name (unsubscripted), in which case the value provides the name of (or a reference to) the actual subroutine to use. In place of a SUBNAME, you can provide a BLOCK as an anonymous, in-line sort subroutine.If the subroutine's prototype is
($$)
, the elements to be compared are passed by reference in @_ , as for a normal subroutine. This is slower than unprototyped subroutines, where the elements to be compared are passed into the subroutine as the package global variables$a
and$b
(see example below).If the subroutine is an XSUB, the elements to be compared are pushed on to the stack, the way arguments are usually passed to XSUBs.
$a
and$b
are not set.The values to be compared are always passed by reference and should not be modified.
You also cannot exit out of the sort block or subroutine using any of the loop control operators described in perlsyn or with goto.
When use locale (but not
use locale ':not_characters'
) is in effect,sort LIST
sorts LIST according to the current collation locale. See perllocale.sort returns aliases into the original list, much as a for loop's index variable aliases the list elements. That is, modifying an element of a list returned by sort (for example, in a
foreach
, map or grep) actually modifies the element in the original list. This is usually something to be avoided when writing clear code.Historically Perl has varied in whether sorting is stable by default. If stability matters, it can be controlled explicitly by using the sort pragma.
Examples:
- # sort lexically
- my @articles = sort @files;
- # same thing, but with explicit sort routine
- my @articles = sort {$a cmp $b} @files;
- # now case-insensitively
- my @articles = sort {fc($a) cmp fc($b)} @files;
- # same thing in reversed order
- my @articles = sort {$b cmp $a} @files;
- # sort numerically ascending
- my @articles = sort {$a <=> $b} @files;
- # sort numerically descending
- my @articles = sort {$b <=> $a} @files;
- # this sorts the %age hash by value instead of key
- # using an in-line function
- my @eldest = sort { $age{$b} <=> $age{$a} } keys %age;
- # sort using explicit subroutine name
- sub byage {
- $age{$a} <=> $age{$b}; # presuming numeric
- }
- my @sortedclass = sort byage @class;
- sub backwards { $b cmp $a }
- my @harry = qw(dog cat x Cain Abel);
- my @george = qw(gone chased yz Punished Axed);
- print sort @harry;
- # prints AbelCaincatdogx
- print sort backwards @harry;
- # prints xdogcatCainAbel
- print sort @george, 'to', @harry;
- # prints AbelAxedCainPunishedcatchaseddoggonetoxyz
- # inefficiently sort by descending numeric compare using
- # the first integer after the first = sign, or the
- # whole record case-insensitively otherwise
- my @new = sort {
- ($b =~ /=(\d+)/)[0] <=> ($a =~ /=(\d+)/)[0]
- ||
- fc($a) cmp fc($b)
- } @old;
- # same thing, but much more efficiently;
- # we'll build auxiliary indices instead
- # for speed
- my (@nums, @caps);
- for (@old) {
- push @nums, ( /=(\d+)/ ? $1 : undef );
- push @caps, fc($_);
- }
- my @new = @old[ sort {
- $nums[$b] <=> $nums[$a]
- ||
- $caps[$a] cmp $caps[$b]
- } 0..$#old
- ];
- # same thing, but without any temps
- my @new = map { $_->[0] }
- sort { $b->[1] <=> $a->[1]
- ||
- $a->[2] cmp $b->[2]
- } map { [$_, /=(\d+)/, fc($_)] } @old;
- # using a prototype allows you to use any comparison subroutine
- # as a sort subroutine (including other package's subroutines)
- package Other;
- sub backwards ($$) { $_[1] cmp $_[0]; } # $a and $b are
- # not set here
- package main;
- my @new = sort Other::backwards @old;
- # guarantee stability
- use sort 'stable';
- my @new = sort { substr($a, 3, 5) cmp substr($b, 3, 5) } @old;
Warning: syntactical care is required when sorting the list returned from a function. If you want to sort the list returned by the function call
find_records(@key)
, you can use:If instead you want to sort the array
@key
with the comparison routinefind_records()
then you can use:$a
and$b
are set as package globals in the package the sort() is called from. That means$main::a
and$main::b
(or$::a
and$::b
) in themain
package,$FooPack::a
and$FooPack::b
in theFooPack
package, etc. If the sort block is in scope of amy
orstate
declaration of$a
and/or$b
, you must spell out the full name of the variables in the sort block :- package main;
- my $a = "C"; # DANGER, Will Robinson, DANGER !!!
- print sort { $a cmp $b } qw(A C E G B D F H);
- # WRONG
- sub badlexi { $a cmp $b }
- print sort badlexi qw(A C E G B D F H);
- # WRONG
- # the above prints BACFEDGH or some other incorrect ordering
- print sort { $::a cmp $::b } qw(A C E G B D F H);
- # OK
- print sort { our $a cmp our $b } qw(A C E G B D F H);
- # also OK
- print sort { our ($a, $b); $a cmp $b } qw(A C E G B D F H);
- # also OK
- sub lexi { our $a cmp our $b }
- print sort lexi qw(A C E G B D F H);
- # also OK
- # the above print ABCDEFGH
With proper care you may mix package and my (or state)
$a
and/or$b
:$a
and$b
are implicitly local to the sort() execution and regain their former values upon completing the sort.Sort subroutines written using
$a
and$b
are bound to their calling package. It is possible, but of limited interest, to define them in a different package, since the subroutine must still refer to the calling package's$a
and$b
:Use the prototyped versions (see above) for a more generic alternative.
The comparison function is required to behave. If it returns inconsistent results (sometimes saying
$x[1]
is less than$x[2]
and sometimes saying the opposite, for example) the results are not well-defined.Because
<=>
returns undef when either operand isNaN
(not-a-number), be careful when sorting with a comparison function like$a <=> $b
any lists that might contain aNaN
. The following example takes advantage thatNaN != NaN
to eliminate anyNaN
s from the input list.