Evaluation & Substitutions 3: Grouping arguments with []
You obtain the results of a command by placing the command in square brackets ([]). This is the functional equivalent of the back single quote (`) in sh programming, or using the return value of a function in C.
As the Tcl interpreter reads in a line it replaces all the $variables with their values. If a portion of the string is grouped with square brackets, then the string within the square brackets is evaluated as a command by the interpreter, and the result of the command replaces the square bracketed string.
Let's take the following code segment, for example:
puts [readsensor [selectsensor]]
- The parser scans the entire command, and sees that there is a
command substitution to perform:
readsensor [selectsensor]
, which is sent to the interpreter for evaluation. - The parser once again finds a command to be evaluated and
substituted,
selectsensor
- The fictitious
selectsensor
command is evaluated, and it presumably returns a sensor to read. - At this point, readsensor has a sensor to read, and the readsensor command is evaluated.
- Finally, the value of readsensor is passed on back to the
puts
command, which prints the output to the screen.
The exceptions to this rule are as follows:
- A square bracket that is escaped with a \ is considered as a literal square bracket.
- A square bracket within braces is not modified during the substitution phase.
Example
set x abc puts "A simple substitution: $x\n" set y [set x "def"] puts "Remember that set returns the new value of the variable: X: $x Y: $y\n" set z {[set x "This is a string within quotes within braces"]} puts "Note the curly braces: $z\n" set a "[set x {This is a string within braces within quotes}]" puts "See how the set is executed: $a" puts "\$x is: $x\n" set b "\[set y {This is a string within braces within quotes}]" # Note the \ escapes the bracket, and must be doubled to be a # literal character in double quotes puts "Note the \\ escapes the bracket:\n \$b is: $b" puts "\$y is: $y"